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16433114513 = 144711356679
BaseRepresentation
bin11110100110111110…
…10110110110010001
31120102020210201012212
433103133112312101
5232123334131023
611314350401505
71121141111564
oct172337266621
946366721185
1016433114513
116a73079182
123227500295
13171b7202ca
14b1c6b64db
15662a4ae78
hex3d37d6d91

16433114513 has 4 divisors (see below), whose sum is σ = 16444472640. Its totient is φ = 16421756388.

The previous prime is 16433114501. The next prime is 16433114519. The reversal of 16433114513 is 31541133461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16433114513 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 16433114513.

It is not an unprimeable number, because it can be changed into a prime (16433114519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5676893 + ... + 5679786.

It is an arithmetic number, because the mean of its divisors is an integer number (4111118160).

Almost surely, 216433114513 is an apocalyptic number.

It is an amenable number.

16433114513 is a deficient number, since it is larger than the sum of its proper divisors (11358127).

16433114513 is a wasteful number, since it uses less digits than its factorization.

16433114513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11358126.

The product of its digits is 12960, while the sum is 32.

Adding to 16433114513 its reverse (31541133461), we get a palindrome (47974247974).

The spelling of 16433114513 in words is "sixteen billion, four hundred thirty-three million, one hundred fourteen thousand, five hundred thirteen".

Divisors: 1 1447 11356679 16433114513