Base | Representation |
---|---|
bin | 1110111100100010101000… |
… | …1011001101101110001001 |
3 | 2011012000002121201000210222 |
4 | 3233020222023031232021 |
5 | 4123220300112113403 |
6 | 54541155411515425 |
7 | 3314156213106344 |
oct | 357105213155611 |
9 | 64160077630728 |
10 | 16433252457353 |
11 | 5266337664186 |
12 | 1a14a5abb8b75 |
13 | 922858c96004 |
14 | 40b53348b45b |
15 | 1d76eec0e338 |
hex | ef22a2cdb89 |
16433252457353 has 16 divisors (see below), whose sum is σ = 16941307334400. Its totient is φ = 15932864016000.
The previous prime is 16433252457341. The next prime is 16433252457367. The reversal of 16433252457353 is 35375425233461.
It is a cyclic number.
It is not a de Polignac number, because 16433252457353 - 234 = 16416072588169 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16433252457295 and 16433252457304.
It is not an unprimeable number, because it can be changed into a prime (16433252457383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 175467743 + ... + 175561371.
It is an arithmetic number, because the mean of its divisors is an integer number (1058831708400).
Almost surely, 216433252457353 is an apocalyptic number.
It is an amenable number.
16433252457353 is a deficient number, since it is larger than the sum of its proper divisors (508054877047).
16433252457353 is an equidigital number, since it uses as much as digits as its factorization.
16433252457353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134512.
The product of its digits is 27216000, while the sum is 53.
The spelling of 16433252457353 in words is "sixteen trillion, four hundred thirty-three billion, two hundred fifty-two million, four hundred fifty-seven thousand, three hundred fifty-three".
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