16433363066041 has 4 divisors (see below), whose sum is σ = 16480721461392. Its totient is φ = 16386004670692.

The previous prime is 16433363066017. The next prime is 16433363066053. The reversal of 16433363066041 is 14066036333461.

16433363066041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16433363066041 - 2²³ = 16433354677433 is a prime.

It is a super-2 number, since 2×16433363066041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16433363065982 and 16433363066000.

It is not an unprimeable number, because it can be changed into a prime (16433363066941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23679197155 + ... + 23679197848.

It is an arithmetic number, because the mean of its divisors is an integer number (4120180365348).

Almost surely, 2^{16433363066041} is an apocalyptic number.

It is an amenable number.

16433363066041 is a deficient number, since it is larger than the sum of its proper divisors (47358395351).

16433363066041 is an equidigital number, since it uses as much as digits as its factorization.

16433363066041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47358395350.

The product of its (nonzero) digits is 1679616, while the sum is 46.

The spelling of 16433363066041 in words is "sixteen trillion, four hundred thirty-three billion, three hundred sixty-three million, sixty-six thousand, forty-one".