164403433 has 4 divisors (see below), whose sum is σ = 164567380. Its totient is φ = 164239488.

The previous prime is 164403401. The next prime is 164403439. The reversal of 164403433 is 334304461.

164403433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334304461 = 61 ⋅5480401.

It can be written as a sum of positive squares in 2 ways, for example, as 39790864 + 124612569 = 6308^2 + 11163^2 .

It is a cyclic number.

It is not a de Polignac number, because 164403433 - 2⁵ = 164403401 is a prime.

It is a super-3 number, since 3×164403433³ (a number of 26 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (164403439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80460 + ... + 82477.

It is an arithmetic number, because the mean of its divisors is an integer number (41141845).

Almost surely, 2^164403433 is an apocalyptic number.

It is an amenable number.

164403433 is a deficient number, since it is larger than the sum of its proper divisors (163947).

164403433 is a wasteful number, since it uses less digits than its factorization.

164403433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163946.

The product of its (nonzero) digits is 10368, while the sum is 28.

The square root of 164403433 is about 12821.9902121317. The cubic root of 164403433 is about 547.8188358565.

Adding to 164403433 its reverse (334304461), we get a palindrome (498707894).

It can be divided in two parts, 164403 and 433, that added together give a square (164836 = 406²).

The spelling of 164403433 in words is "one hundred sixty-four million, four hundred three thousand, four hundred thirty-three".