Base | Representation |
---|---|
bin | 1110111100111111100101… |
… | …0111111011111100001011 |
3 | 2011012202011012120011222112 |
4 | 3233033321113323330023 |
5 | 4123332204023042103 |
6 | 54544522455212535 |
7 | 3314552615103422 |
oct | 357177127737413 |
9 | 64182135504875 |
10 | 16441023643403 |
11 | 5269665259297 |
12 | 1a1646967714b |
13 | 9234c6ca3958 |
14 | 40ba6d5d22b9 |
15 | 1d7a070accd8 |
hex | ef3f95fbf0b |
16441023643403 has 2 divisors, whose sum is σ = 16441023643404. Its totient is φ = 16441023643402.
The previous prime is 16441023643393. The next prime is 16441023643409. The reversal of 16441023643403 is 30434632014461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16441023643403 - 220 = 16441022594827 is a prime.
It is a super-3 number, since 3×164410236434033 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (16441023643409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220511821701 + 8220511821702.
It is an arithmetic number, because the mean of its divisors is an integer number (8220511821702).
Almost surely, 216441023643403 is an apocalyptic number.
16441023643403 is a deficient number, since it is larger than the sum of its proper divisors (1).
16441023643403 is an equidigital number, since it uses as much as digits as its factorization.
16441023643403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 41.
Adding to 16441023643403 its reverse (30434632014461), we get a palindrome (46875655657864).
The spelling of 16441023643403 in words is "sixteen trillion, four hundred forty-one billion, twenty-three million, six hundred forty-three thousand, four hundred three".
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