Base | Representation |
---|---|
bin | 11110100111111011… |
… | …00011101010011011 |
3 | 1120102210200221001001 |
4 | 33103331203222123 |
5 | 232132401000243 |
6 | 11315232205431 |
7 | 1121265313633 |
oct | 172375435233 |
9 | 46383627031 |
10 | 16441031323 |
11 | 6a775961a2 |
12 | 322a099877 |
13 | 1720262902 |
14 | b1d7776c3 |
15 | 6635b1a4d |
hex | 3d3f63a9b |
16441031323 has 4 divisors (see below), whose sum is σ = 16532880840. Its totient is φ = 16349181808.
The previous prime is 16441031317. The next prime is 16441031371. The reversal of 16441031323 is 32313014461.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16441031323 is a prime.
It is a super-3 number, since 3×164410313233 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16441031291 and 16441031300.
It is not an unprimeable number, because it can be changed into a prime (16441031423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45924490 + ... + 45924847.
It is an arithmetic number, because the mean of its divisors is an integer number (4133220210).
Almost surely, 216441031323 is an apocalyptic number.
16441031323 is a deficient number, since it is larger than the sum of its proper divisors (91849517).
16441031323 is an equidigital number, since it uses as much as digits as its factorization.
16441031323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91849516.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 16441031323 its reverse (32313014461), we get a palindrome (48754045784).
The spelling of 16441031323 in words is "sixteen billion, four hundred forty-one million, thirty-one thousand, three hundred twenty-three".
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