Base | Representation |
---|---|
bin | 1110111101000011101110… |
… | …0101100100010001000011 |
3 | 2011012212000121212012012002 |
4 | 3233100323211210101003 |
5 | 4123341442413401312 |
6 | 54545225021054215 |
7 | 3314622264246431 |
oct | 357207345442103 |
9 | 64185017765162 |
10 | 16442134512707 |
11 | 526a0853178a2 |
12 | 1a167196b736b |
13 | 92364318ba77 |
14 | 40bb36d5dd51 |
15 | 1d7a6e88e4c2 |
hex | ef43b964443 |
16442134512707 has 2 divisors, whose sum is σ = 16442134512708. Its totient is φ = 16442134512706.
The previous prime is 16442134512703. The next prime is 16442134512721. The reversal of 16442134512707 is 70721543124461.
16442134512707 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (70721543124461) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16442134512707 - 22 = 16442134512703 is a prime.
It is a super-3 number, since 3×164421345127073 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (16442134512701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221067256353 + 8221067256354.
It is an arithmetic number, because the mean of its divisors is an integer number (8221067256354).
Almost surely, 216442134512707 is an apocalyptic number.
16442134512707 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442134512707 is an equidigital number, since it uses as much as digits as its factorization.
16442134512707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1128960, while the sum is 47.
The spelling of 16442134512707 in words is "sixteen trillion, four hundred forty-two billion, one hundred thirty-four million, five hundred twelve thousand, seven hundred seven".
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