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16442575640641 = 17860392062147
BaseRepresentation
bin1110111101000101010111…
…1000010101100001000001
32011012220011100220210221201
43233101111320111201001
54123343343331000031
654545340500021201
73314636231624623
oct357212570254101
964186140823851
1016442575640641
11526a291323837
121a16821391801
139236b36a0407
1440bb7978cc13
151d7a98478d61
hexef455e15841

16442575640641 has 4 divisors (see below), whose sum is σ = 16442667881392. Its totient is φ = 16442483399892.

The previous prime is 16442575640639. The next prime is 16442575640683. The reversal of 16442575640641 is 14604657524461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16442575640641 - 21 = 16442575640639 is a prime.

It is a super-3 number, since 3×164425756406413 (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16442575640611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45852471 + ... + 46209676.

It is an arithmetic number, because the mean of its divisors is an integer number (4110666970348).

Almost surely, 216442575640641 is an apocalyptic number.

It is an amenable number.

16442575640641 is a deficient number, since it is larger than the sum of its proper divisors (92240751).

16442575640641 is an equidigital number, since it uses as much as digits as its factorization.

16442575640641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92240750.

The product of its (nonzero) digits is 19353600, while the sum is 55.

The spelling of 16442575640641 in words is "sixteen trillion, four hundred forty-two billion, five hundred seventy-five million, six hundred forty thousand, six hundred forty-one".

Divisors: 1 178603 92062147 16442575640641