Base | Representation |
---|---|
bin | 1110111101000101101100… |
… | …1000011101101111010011 |
3 | 2011012220101111201110201122 |
4 | 3233101123020131233103 |
5 | 4123344033410122312 |
6 | 54545353324352455 |
7 | 3314641351604141 |
oct | 357213310355723 |
9 | 64186344643648 |
10 | 16442663754707 |
11 | 526a327037183 |
12 | 1a168469a572b |
13 | 9236c8a11b08 |
14 | 40bb87368591 |
15 | 1d7aa1081b72 |
hex | ef45b21dbd3 |
16442663754707 has 2 divisors, whose sum is σ = 16442663754708. Its totient is φ = 16442663754706.
The previous prime is 16442663754619. The next prime is 16442663754793. The reversal of 16442663754707 is 70745736624461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16442663754707 - 240 = 15343152126931 is a prime.
It is a super-3 number, since 3×164426637547073 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 16442663754707.
It is not a weakly prime, because it can be changed into another prime (16442663754007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221331877353 + 8221331877354.
It is an arithmetic number, because the mean of its divisors is an integer number (8221331877354).
Almost surely, 216442663754707 is an apocalyptic number.
16442663754707 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442663754707 is an equidigital number, since it uses as much as digits as its factorization.
16442663754707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 142248960, while the sum is 62.
The spelling of 16442663754707 in words is "sixteen trillion, four hundred forty-two billion, six hundred sixty-three million, seven hundred fifty-four thousand, seven hundred seven".
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