Base | Representation |
---|---|
bin | 1110111101000111011001… |
… | …0111011001111111000011 |
3 | 2011012221120100110110220201 |
4 | 3233101312113121333003 |
5 | 4123401002342000243 |
6 | 54545510525350031 |
7 | 3314655600316624 |
oct | 357216627317703 |
9 | 64187510413821 |
10 | 16443120656323 |
11 | 526a540a37119 |
12 | 1a16953a08317 |
13 | 92376c586cba |
14 | 40bbcbd01a4b |
15 | 1d7acb23504d |
hex | ef4765d9fc3 |
16443120656323 has 2 divisors, whose sum is σ = 16443120656324. Its totient is φ = 16443120656322.
The previous prime is 16443120656293. The next prime is 16443120656341. The reversal of 16443120656323 is 32365602134461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16443120656323 - 213 = 16443120648131 is a prime.
It is a super-3 number, since 3×164431206563233 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (16443120656353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221560328161 + 8221560328162.
It is an arithmetic number, because the mean of its divisors is an integer number (8221560328162).
Almost surely, 216443120656323 is an apocalyptic number.
16443120656323 is a deficient number, since it is larger than the sum of its proper divisors (1).
16443120656323 is an equidigital number, since it uses as much as digits as its factorization.
16443120656323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 46.
The spelling of 16443120656323 in words is "sixteen trillion, four hundred forty-three billion, one hundred twenty million, six hundred fifty-six thousand, three hundred twenty-three".
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