16444325430131 has 4 divisors (see below), whose sum is σ = 16444502845032. Its totient is φ = 16444148015232.

The previous prime is 16444325430097. The next prime is 16444325430133. The reversal of 16444325430131 is 13103452344461.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16444325430131 is a prime.

It is a super-2 number, since 2×16444325430131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16444325430133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88568345 + ... + 88753818.

It is an arithmetic number, because the mean of its divisors is an integer number (4111125711258).

Almost surely, 2^{16444325430131} is an apocalyptic number.

16444325430131 is a deficient number, since it is larger than the sum of its proper divisors (177414901).

16444325430131 is an equidigital number, since it uses as much as digits as its factorization.

16444325430131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177414900.

The product of its (nonzero) digits is 414720, while the sum is 41.

Adding to 16444325430131 its reverse (13103452344461), we get a palindrome (29547777774592).

The spelling of 16444325430131 in words is "sixteen trillion, four hundred forty-four billion, three hundred twenty-five million, four hundred thirty thousand, one hundred thirty-one".