Base | Representation |
---|---|
bin | 1001100101101010111… |
… | …0100111001101011001 |
3 | 120202012101022002022012 |
4 | 2121122232213031121 |
5 | 10144332104112123 |
6 | 203402031235305 |
7 | 14621120524061 |
oct | 2313256471531 |
9 | 522171262265 |
10 | 164730925913 |
11 | 63953349894 |
12 | 27b14078b35 |
13 | 126c3437c78 |
14 | 7d89d723a1 |
15 | 4441e93378 |
hex | 265aba7359 |
164730925913 has 2 divisors, whose sum is σ = 164730925914. Its totient is φ = 164730925912.
The previous prime is 164730925867. The next prime is 164730925921. The reversal of 164730925913 is 319529037461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102314897689 + 62416028224 = 319867^2 + 249832^2 .
It is a cyclic number.
It is not a de Polignac number, because 164730925913 - 210 = 164730924889 is a prime.
It is not a weakly prime, because it can be changed into another prime (164730925313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82365462956 + 82365462957.
It is an arithmetic number, because the mean of its divisors is an integer number (82365462957).
Almost surely, 2164730925913 is an apocalyptic number.
It is an amenable number.
164730925913 is a deficient number, since it is larger than the sum of its proper divisors (1).
164730925913 is an equidigital number, since it uses as much as digits as its factorization.
164730925913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1224720, while the sum is 50.
The spelling of 164730925913 in words is "one hundred sixty-four billion, seven hundred thirty million, nine hundred twenty-five thousand, nine hundred thirteen".
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