Base | Representation |
---|---|
bin | 100101100100001010001010… |
… | …011010010010011100000011 |
3 | 210122222011102120022220102220 |
4 | 211210022022122102130003 |
5 | 133123320232220430021 |
6 | 1343213331310142123 |
7 | 46541132416433130 |
oct | 4544121232223403 |
9 | 718864376286386 |
10 | 165212534155011 |
11 | 487072734a3132 |
12 | 166433674b1943 |
13 | 7125623ac2715 |
14 | 2cb2487917587 |
15 | 14178555ebcc6 |
hex | 96428a692703 |
165212534155011 has 8 divisors (see below), whose sum is σ = 251752432998144. Its totient is φ = 94407162374280.
The previous prime is 165212534154973. The next prime is 165212534155027. The reversal of 165212534155011 is 110551435212561.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 165212534155011 - 215 = 165212534122243 is a prime.
It is not an unprimeable number, because it can be changed into a prime (165212534145011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3933631765575 + ... + 3933631765616.
It is an arithmetic number, because the mean of its divisors is an integer number (31469054124768).
Almost surely, 2165212534155011 is an apocalyptic number.
165212534155011 is a deficient number, since it is larger than the sum of its proper divisors (86539898843133).
165212534155011 is an equidigital number, since it uses as much as digits as its factorization.
165212534155011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7867263531201.
The product of its (nonzero) digits is 180000, while the sum is 42.
Adding to 165212534155011 its reverse (110551435212561), we get a palindrome (275763969367572).
The spelling of 165212534155011 in words is "one hundred sixty-five trillion, two hundred twelve billion, five hundred thirty-four million, one hundred fifty-five thousand, eleven".
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