Base | Representation |
---|---|
bin | 1111000011000101101000… |
… | …0000010100001001000011 |
3 | 2011120202101221212020022112 |
4 | 3300301122000110021003 |
5 | 4132041120324244011 |
6 | 55105000052325535 |
7 | 3325250315656214 |
oct | 360613200241103 |
9 | 64522357766275 |
10 | 16545724056131 |
11 | 52aa00297a006 |
12 | 1a328096138ab |
13 | 930341559caa |
14 | 412b62a0b40b |
15 | 1da5d3cc258b |
hex | f0c5a014243 |
16545724056131 has 2 divisors, whose sum is σ = 16545724056132. Its totient is φ = 16545724056130.
The previous prime is 16545724056079. The next prime is 16545724056149. The reversal of 16545724056131 is 13165042754561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16545724056131 - 218 = 16545723793987 is a prime.
It is a super-2 number, since 2×165457240561312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 16545724056131.
It is not a weakly prime, because it can be changed into another prime (16545724086131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8272862028065 + 8272862028066.
It is an arithmetic number, because the mean of its divisors is an integer number (8272862028066).
Almost surely, 216545724056131 is an apocalyptic number.
16545724056131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16545724056131 is an equidigital number, since it uses as much as digits as its factorization.
16545724056131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024000, while the sum is 50.
The spelling of 16545724056131 in words is "sixteen trillion, five hundred forty-five billion, seven hundred twenty-four million, fifty-six thousand, one hundred thirty-one".
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