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1656150113 = 1918670943
BaseRepresentation
bin110001010110110…
…1101100001100001
311021102100010212002
41202231231201201
511342433300423
6432201013345
756020020662
oct14255554141
94242303762
101656150113
1177a943102
123a2784255
132051655a7
14119d4d369
159a5e1228
hex62b6d861

1656150113 has 4 divisors (see below), whose sum is σ = 1664821248. Its totient is φ = 1647478980.

The previous prime is 1656150079. The next prime is 1656150127. The reversal of 1656150113 is 3110516561.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1656150113 - 212 = 1656146017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1656150163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4335281 + ... + 4335662.

It is an arithmetic number, because the mean of its divisors is an integer number (416205312).

Almost surely, 21656150113 is an apocalyptic number.

It is an amenable number.

1656150113 is a deficient number, since it is larger than the sum of its proper divisors (8671135).

1656150113 is an equidigital number, since it uses as much as digits as its factorization.

1656150113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8671134.

The product of its (nonzero) digits is 2700, while the sum is 29.

The square root of 1656150113 is about 40695.8242698191. The cubic root of 1656150113 is about 1183.1320872781.

Adding to 1656150113 its reverse (3110516561), we get a palindrome (4766666674).

The spelling of 1656150113 in words is "one billion, six hundred fifty-six million, one hundred fifty thousand, one hundred thirteen".

Divisors: 1 191 8670943 1656150113