Base | Representation |
---|---|
bin | 1111000110010001101100… |
… | …1101010000111010010011 |
3 | 2011202222210201222121200012 |
4 | 3301210123031100322103 |
5 | 4133440313243423021 |
6 | 55150100003345135 |
7 | 3332226663556544 |
oct | 361443315207223 |
9 | 64688721877605 |
10 | 16600505061011 |
11 | 5320264372863 |
12 | 1a413576821ab |
13 | 935561980391 |
14 | 41567c2b44cb |
15 | 1dbc3d26135b |
hex | f191b350e93 |
16600505061011 has 2 divisors, whose sum is σ = 16600505061012. Its totient is φ = 16600505061010.
The previous prime is 16600505060989. The next prime is 16600505061061. The reversal of 16600505061011 is 11016050500661.
16600505061011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (11016050500661) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16600505061011 - 242 = 12202458549907 is a prime.
It is not a weakly prime, because it can be changed into another prime (16600505061061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8300252530505 + 8300252530506.
It is an arithmetic number, because the mean of its divisors is an integer number (8300252530506).
Almost surely, 216600505061011 is an apocalyptic number.
16600505061011 is a deficient number, since it is larger than the sum of its proper divisors (1).
16600505061011 is an equidigital number, since it uses as much as digits as its factorization.
16600505061011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 32.
Adding to 16600505061011 its reverse (11016050500661), we get a palindrome (27616555561672).
The spelling of 16600505061011 in words is "sixteen trillion, six hundred billion, five hundred five million, sixty-one thousand, eleven".
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