1660253131 has 4 divisors (see below), whose sum is σ = 1660335264. Its totient is φ = 1660171000.

The previous prime is 1660253129. The next prime is 1660253171. The reversal of 1660253131 is 1313520661.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1313520661 = 71 ⋅18500291.

It is a cyclic number.

It is not a de Polignac number, because 1660253131 - 2¹ = 1660253129 is a prime.

It is a super-3 number, since 3×1660253131³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1660253131.

It is not an unprimeable number, because it can be changed into a prime (1660253171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12861 + ... + 59041.

It is an arithmetic number, because the mean of its divisors is an integer number (415083816).

Almost surely, 2^1660253131 is an apocalyptic number.

1660253131 is a deficient number, since it is larger than the sum of its proper divisors (82133).

1660253131 is an equidigital number, since it uses as much as digits as its factorization.

1660253131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82132.

The product of its (nonzero) digits is 3240, while the sum is 28.

The square root of 1660253131 is about 40746.2038845338. The cubic root of 1660253131 is about 1184.1083290807.

Adding to 1660253131 its reverse (1313520661), we get a palindrome (2973773792).

The spelling of 1660253131 in words is "one billion, six hundred sixty million, two hundred fifty-three thousand, one hundred thirty-one".