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166052233136650 = 252747283202717597
BaseRepresentation
bin100101110000011000001100…
…010111101100101000001010
3210202221102211122002212100211
4211300120030113230220022
5133231044433140333100
61345055202013351334
746655610064135330
oct4560301427545012
9722842748085324
10166052233136650
1148a003a16a6363
121675a050a9854a
137186873658173
142d00d8448db50
15142e5edc651ba
hex97060c5eca0a

166052233136650 has 192 divisors, whose sum is σ = 361962664906752. Its totient is φ = 55493431453440.

The previous prime is 166052233136611. The next prime is 166052233136653. The reversal of 166052233136650 is 56631332250661.

It is a super-3 number, since 3×1660522331366503 (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 166052233136594 and 166052233136603.

It is not an unprimeable number, because it can be changed into a prime (166052233136653) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 9436385652 + ... + 9436403248.

It is an arithmetic number, because the mean of its divisors is an integer number (1885222213056).

Almost surely, 2166052233136650 is an apocalyptic number.

166052233136650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

166052233136650 is an abundant number, since it is smaller than the sum of its proper divisors (195910431770102).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

166052233136650 is a wasteful number, since it uses less digits than its factorization.

166052233136650 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19973 (or 19968 counting only the distinct ones).

The product of its (nonzero) digits is 3499200, while the sum is 49.

The spelling of 166052233136650 in words is "one hundred sixty-six trillion, fifty-two billion, two hundred thirty-three million, one hundred thirty-six thousand, six hundred fifty".