Base | Representation |
---|---|
bin | 10011110011010… |
… | …11000010011001 |
3 | 102120120102210101 |
4 | 21321223002121 |
5 | 320011112213 |
6 | 24252215401 |
7 | 4054640503 |
oct | 1171530231 |
9 | 376512711 |
10 | 166113433 |
11 | 85848532 |
12 | 4776a561 |
13 | 28551295 |
14 | 180c0d73 |
15 | e8b3bdd |
hex | 9e6b099 |
166113433 has 2 divisors, whose sum is σ = 166113434. Its totient is φ = 166113432.
The previous prime is 166113413. The next prime is 166113449. The reversal of 166113433 is 334311661.
166113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 143712144 + 22401289 = 11988^2 + 4733^2 .
It is a cyclic number.
It is not a de Polignac number, because 166113433 - 25 = 166113401 is a prime.
It is the 12889-th Hogben number.
It is not a weakly prime, because it can be changed into another prime (166113413) by changing a digit.
It is a nontrivial repunit in base 12888.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83056716 + 83056717.
It is an arithmetic number, because the mean of its divisors is an integer number (83056717).
Almost surely, 2166113433 is an apocalyptic number.
It is an amenable number.
166113433 is a deficient number, since it is larger than the sum of its proper divisors (1).
166113433 is an equidigital number, since it uses as much as digits as its factorization.
166113433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3888, while the sum is 28.
The square root of 166113433 is about 12888.5000290957. The cubic root of 166113433 is about 549.7116207225.
The spelling of 166113433 in words is "one hundred sixty-six million, one hundred thirteen thousand, four hundred thirty-three".
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