1662141101233 has 4 divisors (see below), whose sum is σ = 1664378169408. Its totient is φ = 1659904033060.

The previous prime is 1662141101227. The next prime is 1662141101237. The reversal of 1662141101233 is 3321011412661.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1662141101233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1662141101195 and 1662141101204.

It is not an unprimeable number, because it can be changed into a prime (1662141101237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1118532973 + ... + 1118534458.

It is an arithmetic number, because the mean of its divisors is an integer number (416094542352).

Almost surely, 2^{1662141101233} is an apocalyptic number.

It is an amenable number.

1662141101233 is a deficient number, since it is larger than the sum of its proper divisors (2237068175).

1662141101233 is an equidigital number, since it uses as much as digits as its factorization.

1662141101233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2237068174.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 1662141101233 its reverse (3321011412661), we get a palindrome (4983152513894).

The spelling of 1662141101233 in words is "one trillion, six hundred sixty-two billion, one hundred forty-one million, one hundred one thousand, two hundred thirty-three".