Base | Representation |
---|---|
bin | 11111000011001101… |
… | …01011000100011011 |
3 | 1121000202101100011221 |
4 | 33201212223010123 |
5 | 233114444211441 |
6 | 11354050032511 |
7 | 1130044632346 |
oct | 174146530433 |
9 | 47022340157 |
10 | 16669913371 |
11 | 7084805711 |
12 | 3292878737 |
13 | 17587c0087 |
14 | b41d1745d |
15 | 6787238d1 |
hex | 3e19ab11b |
16669913371 has 8 divisors (see below), whose sum is σ = 17801020800. Its totient is φ = 15575891520.
The previous prime is 16669913353. The next prime is 16669913387. The reversal of 16669913371 is 17331996661.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 16669913371 - 217 = 16669782299 is a prime.
It is a super-3 number, since 3×166699133713 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16669913311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9270466 + ... + 9272263.
It is an arithmetic number, because the mean of its divisors is an integer number (2225127600).
Almost surely, 216669913371 is an apocalyptic number.
16669913371 is a deficient number, since it is larger than the sum of its proper divisors (1131107429).
16669913371 is a wasteful number, since it uses less digits than its factorization.
16669913371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18542789.
The product of its digits is 1102248, while the sum is 52.
The spelling of 16669913371 in words is "sixteen billion, six hundred sixty-nine million, nine hundred thirteen thousand, three hundred seventy-one".
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