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166711331 is a prime number
BaseRepresentation
bin10011110111111…
…01000000100011
3102121200210221202
421323331000203
5320134230311
624313111415
74063010603
oct1173750043
9377623852
10166711331
1186116766
12479b856b
1328700477
14181d8c03
15e980e3b
hex9efd023

166711331 has 2 divisors, whose sum is σ = 166711332. Its totient is φ = 166711330.

The previous prime is 166711261. The next prime is 166711373. The reversal of 166711331 is 133117661.

It is a strong prime.

It is an emirp because it is prime and its reverse (133117661) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 166711331 - 210 = 166710307 is a prime.

It is a super-3 number, since 3×1667113313 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 166711294 and 166711303.

It is not a weakly prime, because it can be changed into another prime (166711631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83355665 + 83355666.

It is an arithmetic number, because the mean of its divisors is an integer number (83355666).

Almost surely, 2166711331 is an apocalyptic number.

166711331 is a deficient number, since it is larger than the sum of its proper divisors (1).

166711331 is an equidigital number, since it uses as much as digits as its factorization.

166711331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2268, while the sum is 29.

The square root of 166711331 is about 12911.6742136719. The cubic root of 166711331 is about 550.3703632182.

Adding to 166711331 its reverse (133117661), we get a palindrome (299828992).

The spelling of 166711331 in words is "one hundred sixty-six million, seven hundred eleven thousand, three hundred thirty-one".