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16671342502489 is a prime number
BaseRepresentation
bin1111001010011001100101…
…1100101010001001011001
32012000202122112010111021211
43302212121130222021121
54141120402140034424
655242413051503121
73340315260103543
oct362463134521131
965022575114254
1016671342502489
115348305249024
121a53026a57aa1
1393c140759a1c
14418c7c200693
151dd9d7142b94
hexf299972a259

16671342502489 has 2 divisors, whose sum is σ = 16671342502490. Its totient is φ = 16671342502488.

The previous prime is 16671342502483. The next prime is 16671342502601. The reversal of 16671342502489 is 98420524317661.

16671342502489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14613646928400 + 2057695574089 = 3822780^2 + 1434467^2 .

It is a cyclic number.

It is not a de Polignac number, because 16671342502489 - 29 = 16671342501977 is a prime.

It is not a weakly prime, because it can be changed into another prime (16671342502483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8335671251244 + 8335671251245.

It is an arithmetic number, because the mean of its divisors is an integer number (8335671251245).

It is a 1-persistent number, because it is pandigital, but 2⋅16671342502489 = 33342685004978 is not.

Almost surely, 216671342502489 is an apocalyptic number.

It is an amenable number.

16671342502489 is a deficient number, since it is larger than the sum of its proper divisors (1).

16671342502489 is an equidigital number, since it uses as much as digits as its factorization.

16671342502489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17418240, while the sum is 58.

The spelling of 16671342502489 in words is "sixteen trillion, six hundred seventy-one billion, three hundred forty-two million, five hundred two thousand, four hundred eighty-nine".