Base | Representation |
---|---|
bin | 1111001010110000000001… |
… | …1000011101110101101001 |
3 | 2012001100012012102210200101 |
4 | 3302230000120131311221 |
5 | 4141220220243032131 |
6 | 55245250410305401 |
7 | 3340620431433256 |
oct | 362540030356551 |
9 | 65040165383611 |
10 | 16677364424041 |
11 | 534a9154918a2 |
12 | 1a54227728261 |
13 | 93c89022c709 |
14 | 41928dcb842d |
15 | 1ddc3ab5ac61 |
hex | f2b0061dd69 |
16677364424041 has 2 divisors, whose sum is σ = 16677364424042. Its totient is φ = 16677364424040.
The previous prime is 16677364424029. The next prime is 16677364424047. The reversal of 16677364424041 is 14042446377661.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10390791075625 + 6286573348416 = 3223475^2 + 2507304^2 .
It is a cyclic number.
It is not a de Polignac number, because 16677364424041 - 237 = 16539925470569 is a prime.
It is not a weakly prime, because it can be changed into another prime (16677364424047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8338682212020 + 8338682212021.
It is an arithmetic number, because the mean of its divisors is an integer number (8338682212021).
Almost surely, 216677364424041 is an apocalyptic number.
It is an amenable number.
16677364424041 is a deficient number, since it is larger than the sum of its proper divisors (1).
16677364424041 is an equidigital number, since it uses as much as digits as its factorization.
16677364424041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16257024, while the sum is 55.
The spelling of 16677364424041 in words is "sixteen trillion, six hundred seventy-seven billion, three hundred sixty-four million, four hundred twenty-four thousand, forty-one".
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