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16707405423257 = 35416347174339
BaseRepresentation
bin1111001100011111111011…
…1101110010001010011001
32012011012201210212200101222
43303013332331302022121
54142213231242021012
655311135345221425
73343033036631333
oct363077675621231
965135653780358
1016707405423257
11536163088917a
121a5a010331875
13942669c4b0b3
1441a8dd956453
151de8e8182972
hexf31fef72299

16707405423257 has 4 divisors (see below), whose sum is σ = 16707452951760. Its totient is φ = 16707357894756.

The previous prime is 16707405423239. The next prime is 16707405423259. The reversal of 16707405423257 is 75232450470761.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16707405423257 - 28 = 16707405423001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16707405423199 and 16707405423208.

It is not an unprimeable number, because it can be changed into a prime (16707405423259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23233007 + ... + 23941332.

It is an arithmetic number, because the mean of its divisors is an integer number (4176863237940).

Almost surely, 216707405423257 is an apocalyptic number.

It is an amenable number.

16707405423257 is a deficient number, since it is larger than the sum of its proper divisors (47528503).

16707405423257 is an equidigital number, since it uses as much as digits as its factorization.

16707405423257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47528502.

The product of its (nonzero) digits is 9878400, while the sum is 53.

The spelling of 16707405423257 in words is "sixteen trillion, seven hundred seven billion, four hundred five million, four hundred twenty-three thousand, two hundred fifty-seven".

Divisors: 1 354163 47174339 16707405423257