1677140131 has 2 divisors, whose sum is σ = 1677140132. Its totient is φ = 1677140130.

The previous prime is 1677140111. The next prime is 1677140167. The reversal of 1677140131 is 1310417761.

It is a weak prime.

It is an emirp because it is prime and its reverse (1310417761) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1677140131 is a prime.

It is a super-2 number, since 2×1677140131² = 5625598038021394322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1677140093 and 1677140102.

It is not a weakly prime, because it can be changed into another prime (1677140111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 838570065 + 838570066.

It is an arithmetic number, because the mean of its divisors is an integer number (838570066).

Almost surely, 2^1677140131 is an apocalyptic number.

1677140131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1677140131 is an equidigital number, since it uses as much as digits as its factorization.

1677140131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3528, while the sum is 31.

The square root of 1677140131 is about 40952.9013746279. The cubic root of 1677140131 is about 1188.1094503547.

Adding to 1677140131 its reverse (1310417761), we get a palindrome (2987557892).

The spelling of 1677140131 in words is "one billion, six hundred seventy-seven million, one hundred forty thousand, one hundred thirty-one".