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168031925407273 is a prime number
BaseRepresentation
bin100110001101001011111011…
…001110011000111000101001
3211000221200202210101011201211
4212031023323032120320221
5134011013340401013043
61353212444553313121
750251622516605324
oct4615137316307051
9730850683334654
10168031925407273
11495a3a37344524
1216a19867a057a1
13729b45b83b905
142d6cb07c317bb
151465d68e8ca9d
hex98d2fb398e29

168031925407273 has 2 divisors, whose sum is σ = 168031925407274. Its totient is φ = 168031925407272.

The previous prime is 168031925407243. The next prime is 168031925407361. The reversal of 168031925407273 is 372704529130861.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146159588763904 + 21872336643369 = 12089648^2 + 4676787^2 .

It is a cyclic number.

It is not a de Polignac number, because 168031925407273 - 237 = 167894486453801 is a prime.

It is not a weakly prime, because it can be changed into another prime (168031925407243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84015962703636 + 84015962703637.

It is an arithmetic number, because the mean of its divisors is an integer number (84015962703637).

It is a 1-persistent number, because it is pandigital, but 2⋅168031925407273 = 336063850814546 is not.

Almost surely, 2168031925407273 is an apocalyptic number.

It is an amenable number.

168031925407273 is a deficient number, since it is larger than the sum of its proper divisors (1).

168031925407273 is an equidigital number, since it uses as much as digits as its factorization.

168031925407273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 58.

The spelling of 168031925407273 in words is "one hundred sixty-eight trillion, thirty-one billion, nine hundred twenty-five million, four hundred seven thousand, two hundred seventy-three".