168040893313 has 4 divisors (see below), whose sum is σ = 168042373168. Its totient is φ = 168039413460.

The previous prime is 168040893301. The next prime is 168040893337. The reversal of 168040893313 is 313398040861.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313398040861 = 61 ⋅5137672801.

It is a cyclic number.

It is not a de Polignac number, because 168040893313 - 2⁵ = 168040893281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (168040893353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 554031 + ... + 801892.

It is an arithmetic number, because the mean of its divisors is an integer number (42010593292).

Almost surely, 2^168040893313 is an apocalyptic number.

It is an amenable number.

168040893313 is a deficient number, since it is larger than the sum of its proper divisors (1479855).

168040893313 is a wasteful number, since it uses less digits than its factorization.

168040893313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1479854.

The product of its (nonzero) digits is 373248, while the sum is 46.

The spelling of 168040893313 in words is "one hundred sixty-eight billion, forty million, eight hundred ninety-three thousand, three hundred thirteen".