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1683652523713 = 16710081751639
BaseRepresentation
bin11000100000000001100…
…000101011011011000001
312221221210122020222120021
4120200001200223123001
5210041110021224323
63325243112413441
7232432323215566
oct30400140533301
95857718228507
101683652523713
1159a03aa58706
122323779a7281
13c29c999ac94
145b6bc5a886d
152dbe058c05d
hex1880182b6c1

1683652523713 has 4 divisors (see below), whose sum is σ = 1693734275520. Its totient is φ = 1673570771908.

The previous prime is 1683652523677. The next prime is 1683652523747. The reversal of 1683652523713 is 3173252563861.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1683652523713 - 217 = 1683652392641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1683652523753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5040875653 + ... + 5040875986.

It is an arithmetic number, because the mean of its divisors is an integer number (423433568880).

Almost surely, 21683652523713 is an apocalyptic number.

It is an amenable number.

1683652523713 is a deficient number, since it is larger than the sum of its proper divisors (10081751807).

1683652523713 is a wasteful number, since it uses less digits than its factorization.

1683652523713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10081751806.

The product of its digits is 5443200, while the sum is 52.

The spelling of 1683652523713 in words is "one trillion, six hundred eighty-three billion, six hundred fifty-two million, five hundred twenty-three thousand, seven hundred thirteen".

Divisors: 1 167 10081751639 1683652523713