Base | Representation |
---|---|
bin | 11111010111101111… |
… | …11001111111101001 |
3 | 1121110202120120021111 |
4 | 33223313321333221 |
5 | 233443100444423 |
6 | 11423122510321 |
7 | 1134236235661 |
oct | 175367717751 |
9 | 47422516244 |
10 | 16842203113 |
11 | 7162a9152a |
12 | 33205053a1 |
13 | 17853c4678 |
14 | b5ab651a1 |
15 | 68890760d |
hex | 3ebdf9fe9 |
16842203113 has 2 divisors, whose sum is σ = 16842203114. Its totient is φ = 16842203112.
The previous prime is 16842203107. The next prime is 16842203129. The reversal of 16842203113 is 31130224861.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16264666089 + 577537024 = 127533^2 + 24032^2 .
It is an emirp because it is prime and its reverse (31130224861) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16842203113 is a prime.
It is not a weakly prime, because it can be changed into another prime (16842203143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8421101556 + 8421101557.
It is an arithmetic number, because the mean of its divisors is an integer number (8421101557).
Almost surely, 216842203113 is an apocalyptic number.
It is an amenable number.
16842203113 is a deficient number, since it is larger than the sum of its proper divisors (1).
16842203113 is an equidigital number, since it uses as much as digits as its factorization.
16842203113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 16842203113 its reverse (31130224861), we get a palindrome (47972427974).
The spelling of 16842203113 in words is "sixteen billion, eight hundred forty-two million, two hundred three thousand, one hundred thirteen".
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