Base | Representation |
---|---|
bin | 11000100001010011000… |
… | …001010101010010100011 |
3 | 12222002022221110220220221 |
4 | 120201103001111102203 |
5 | 210101410112211212 |
6 | 3330030523143511 |
7 | 232511240001604 |
oct | 30412301252243 |
9 | 5862287426827 |
10 | 1685020038307 |
11 | 59a681979661 |
12 | 232699974b97 |
13 | c2b870b4408 |
14 | 5b7ac061dab |
15 | 2dc70666807 |
hex | 188530554a3 |
1685020038307 has 2 divisors, whose sum is σ = 1685020038308. Its totient is φ = 1685020038306.
The previous prime is 1685020038271. The next prime is 1685020038347. The reversal of 1685020038307 is 7038300205861.
It is a weak prime.
It is an emirp because it is prime and its reverse (7038300205861) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1685020038307 - 27 = 1685020038179 is a prime.
It is a super-2 number, since 2×16850200383072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1685020038347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 842510019153 + 842510019154.
It is an arithmetic number, because the mean of its divisors is an integer number (842510019154).
Almost surely, 21685020038307 is an apocalyptic number.
1685020038307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1685020038307 is an equidigital number, since it uses as much as digits as its factorization.
1685020038307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 43.
The spelling of 1685020038307 in words is "one trillion, six hundred eighty-five billion, twenty million, thirty-eight thousand, three hundred seven".
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