Base | Representation |
---|---|
bin | 11000100001101000010… |
… | …100011010011000000011 |
3 | 12222010020211211211001222 |
4 | 120201220110122120003 |
5 | 210103123101031121 |
6 | 3330130205545255 |
7 | 232523136126122 |
oct | 30415024323003 |
9 | 5863224754058 |
10 | 1685377361411 |
11 | 59a845645807 |
12 | 23277957522b |
13 | c2c131328c3 |
14 | 5b8036b7ab9 |
15 | 2dc91bea0ab |
hex | 1886851a603 |
1685377361411 has 2 divisors, whose sum is σ = 1685377361412. Its totient is φ = 1685377361410.
The previous prime is 1685377361347. The next prime is 1685377361443. The reversal of 1685377361411 is 1141637735861.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1685377361411 - 26 = 1685377361347 is a prime.
It is not a weakly prime, because it can be changed into another prime (1685377361461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 842688680705 + 842688680706.
It is an arithmetic number, because the mean of its divisors is an integer number (842688680706).
Almost surely, 21685377361411 is an apocalyptic number.
1685377361411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1685377361411 is an equidigital number, since it uses as much as digits as its factorization.
1685377361411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2540160, while the sum is 53.
The spelling of 1685377361411 in words is "one trillion, six hundred eighty-five billion, three hundred seventy-seven million, three hundred sixty-one thousand, four hundred eleven".
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