Base | Representation |
---|---|
bin | 1001110110000100101… |
… | …1001100011110100011 |
3 | 121011120020112220220222 |
4 | 2131201023030132203 |
5 | 10232341304033222 |
6 | 205411001353255 |
7 | 15135204461135 |
oct | 2354113143643 |
9 | 534506486828 |
10 | 169134049187 |
11 | 65802841544 |
12 | 2894279882b |
13 | 12c4572275c |
14 | 8286a61055 |
15 | 45ed7e7542 |
hex | 27612cc7a3 |
169134049187 has 2 divisors, whose sum is σ = 169134049188. Its totient is φ = 169134049186.
The previous prime is 169134049169. The next prime is 169134049213. The reversal of 169134049187 is 781940431961.
169134049187 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 169134049187 - 228 = 168865613731 is a prime.
It is not a weakly prime, because it can be changed into another prime (169134049787) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84567024593 + 84567024594.
It is an arithmetic number, because the mean of its divisors is an integer number (84567024594).
Almost surely, 2169134049187 is an apocalyptic number.
169134049187 is a deficient number, since it is larger than the sum of its proper divisors (1).
169134049187 is an equidigital number, since it uses as much as digits as its factorization.
169134049187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 53.
The spelling of 169134049187 in words is "one hundred sixty-nine billion, one hundred thirty-four million, forty-nine thousand, one hundred eighty-seven".
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