Base | Representation |
---|---|
bin | 11111100111010100… |
… | …00111001011100001 |
3 | 1121210212022211011020 |
4 | 33303222013023201 |
5 | 234230014223313 |
6 | 11444110040053 |
7 | 1140413314005 |
oct | 176352071341 |
9 | 47725284136 |
10 | 16972804833 |
11 | 721a784536 |
12 | 33581a9029 |
13 | 17a6490caa |
14 | b70240705 |
15 | 695104323 |
hex | 3f3a872e1 |
16972804833 has 4 divisors (see below), whose sum is σ = 22630406448. Its totient is φ = 11315203220.
The previous prime is 16972804801. The next prime is 16972804889. The reversal of 16972804833 is 33840827961.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16972804833 - 25 = 16972804801 is a prime.
It is a super-2 number, since 2×169728048332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (16972804033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2828800803 + ... + 2828800808.
It is an arithmetic number, because the mean of its divisors is an integer number (5657601612).
Almost surely, 216972804833 is an apocalyptic number.
It is an amenable number.
16972804833 is a deficient number, since it is larger than the sum of its proper divisors (5657601615).
16972804833 is an equidigital number, since it uses as much as digits as its factorization.
16972804833 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5657601614.
The product of its (nonzero) digits is 1741824, while the sum is 51.
The spelling of 16972804833 in words is "sixteen billion, nine hundred seventy-two million, eight hundred four thousand, eight hundred thirty-three".
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