Base | Representation |
---|---|
bin | 11111101001101111… |
… | …01010001110111001 |
3 | 1121212021120121211201 |
4 | 33310313222032321 |
5 | 234300220232442 |
6 | 11450113454201 |
7 | 1141051152154 |
oct | 176467521671 |
9 | 47767517751 |
10 | 16993133497 |
11 | 72301a978a |
12 | 3362b71361 |
13 | 17aa75aba2 |
14 | b72c12c9b |
15 | 696cbc7b7 |
hex | 3f4dea3b9 |
16993133497 has 2 divisors, whose sum is σ = 16993133498. Its totient is φ = 16993133496.
The previous prime is 16993133491. The next prime is 16993133519. The reversal of 16993133497 is 79433139961.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9105739776 + 7887393721 = 95424^2 + 88811^2 .
It is a cyclic number.
It is not a de Polignac number, because 16993133497 - 227 = 16858915769 is a prime.
It is not a weakly prime, because it can be changed into another prime (16993133491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8496566748 + 8496566749.
It is an arithmetic number, because the mean of its divisors is an integer number (8496566749).
Almost surely, 216993133497 is an apocalyptic number.
It is an amenable number.
16993133497 is a deficient number, since it is larger than the sum of its proper divisors (1).
16993133497 is an equidigital number, since it uses as much as digits as its factorization.
16993133497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3306744, while the sum is 55.
The spelling of 16993133497 in words is "sixteen billion, nine hundred ninety-three million, one hundred thirty-three thousand, four hundred ninety-seven".
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