Base | Representation |
---|---|
bin | 11000101111010011101… |
… | …001001111011001000001 |
3 | 20000112011022020201211101 |
4 | 120233103221033121001 |
5 | 210323212044313231 |
6 | 3340555331414401 |
7 | 233553100045024 |
oct | 30572351173101 |
9 | 6015138221741 |
10 | 1700062885441 |
11 | 5a5aa11a6328 |
12 | 235597754401 |
13 | c4413782bab |
14 | 5c3d7c3b1bb |
15 | 2e3510e1661 |
hex | 18bd3a4f641 |
1700062885441 has 2 divisors, whose sum is σ = 1700062885442. Its totient is φ = 1700062885440.
The previous prime is 1700062885399. The next prime is 1700062885457. The reversal of 1700062885441 is 1445882600071.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1662075316225 + 37987569216 = 1289215^2 + 194904^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1700062885441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1700062885391 and 1700062885400.
It is not a weakly prime, because it can be changed into another prime (1700062885141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850031442720 + 850031442721.
It is an arithmetic number, because the mean of its divisors is an integer number (850031442721).
Almost surely, 21700062885441 is an apocalyptic number.
It is an amenable number.
1700062885441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1700062885441 is an equidigital number, since it uses as much as digits as its factorization.
1700062885441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 430080, while the sum is 46.
The spelling of 1700062885441 in words is "one trillion, seven hundred billion, sixty-two million, eight hundred eighty-five thousand, four hundred forty-one".
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