Base | Representation |
---|---|
bin | 1111011110001111000001… |
… | …1111110110000100001001 |
3 | 2020020100012212120211122112 |
4 | 3313203300133312010021 |
5 | 4212211242433400123 |
6 | 100103130414432105 |
7 | 3404040554516141 |
oct | 367436037660411 |
9 | 66210185524575 |
10 | 17012105371913 |
11 | 546987aa83463 |
12 | 1aa9087802635 |
13 | 9653086c02c2 |
14 | 42b566d71921 |
15 | 1e77cd278d78 |
hex | f78f07f6109 |
17012105371913 has 2 divisors, whose sum is σ = 17012105371914. Its totient is φ = 17012105371912.
The previous prime is 17012105371897. The next prime is 17012105371927. The reversal of 17012105371913 is 31917350121071.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16066693355584 + 945412016329 = 4008328^2 + 972323^2 .
It is a cyclic number.
It is not a de Polignac number, because 17012105371913 - 24 = 17012105371897 is a prime.
It is not a weakly prime, because it can be changed into another prime (17012105301913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8506052685956 + 8506052685957.
It is an arithmetic number, because the mean of its divisors is an integer number (8506052685957).
Almost surely, 217012105371913 is an apocalyptic number.
It is an amenable number.
17012105371913 is a deficient number, since it is larger than the sum of its proper divisors (1).
17012105371913 is an equidigital number, since it uses as much as digits as its factorization.
17012105371913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39690, while the sum is 41.
Adding to 17012105371913 its reverse (31917350121071), we get a palindrome (48929455492984).
The spelling of 17012105371913 in words is "seventeen trillion, twelve billion, one hundred five million, three hundred seventy-one thousand, nine hundred thirteen".
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