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17041991313 = 35680663771
BaseRepresentation
bin11111101111100100…
…00010011010010001
31121222200111212011110
433313302002122101
5234400222210223
611455021003533
71142213351604
oct176762023221
947880455143
1017041991313
11725583a346
1233773b35a9
1317b7906439
14b794d033b
1569b21dd93
hex3f7c82691

17041991313 has 4 divisors (see below), whose sum is σ = 22722655088. Its totient is φ = 11361327540.

The previous prime is 17041991303. The next prime is 17041991333. The reversal of 17041991313 is 31319914071.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31319914071 = 310439971357.

It is not a de Polignac number, because 17041991313 - 212 = 17041987217 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17041991303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2840331883 + ... + 2840331888.

It is an arithmetic number, because the mean of its divisors is an integer number (5680663772).

Almost surely, 217041991313 is an apocalyptic number.

It is an amenable number.

17041991313 is a deficient number, since it is larger than the sum of its proper divisors (5680663775).

17041991313 is an equidigital number, since it uses as much as digits as its factorization.

17041991313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5680663774.

The product of its (nonzero) digits is 20412, while the sum is 39.

The spelling of 17041991313 in words is "seventeen billion, forty-one million, nine hundred ninety-one thousand, three hundred thirteen".

Divisors: 1 3 5680663771 17041991313