17044893113 has 4 divisors (see below), whose sum is σ = 17045160528. Its totient is φ = 17044625700.

The previous prime is 17044893083. The next prime is 17044893133. The reversal of 17044893113 is 31139844071.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31139844071 = 7 ⋅4448549153.

It is a cyclic number.

It is not a de Polignac number, because 17044893113 - 2⁶ = 17044893049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17044893133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23570 + ... + 186132.

It is an arithmetic number, because the mean of its divisors is an integer number (4261290132).

Almost surely, 2^17044893113 is an apocalyptic number.

It is an amenable number.

17044893113 is a deficient number, since it is larger than the sum of its proper divisors (267415).

17044893113 is a wasteful number, since it uses less digits than its factorization.

17044893113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267414.

The product of its (nonzero) digits is 72576, while the sum is 41.

The spelling of 17044893113 in words is "seventeen billion, forty-four million, eight hundred ninety-three thousand, one hundred thirteen".