Base | Representation |
---|---|
bin | 11000110110110011010… |
… | …111111001000001010001 |
3 | 20001021221012221200121202 |
4 | 120312303113321001101 |
5 | 210441203004313131 |
6 | 3344410123200545 |
7 | 234256410231053 |
oct | 30666327710121 |
9 | 6037835850552 |
10 | 1708111401041 |
11 | 5a94513a0211 |
12 | 237063076155 |
13 | c50c7081866 |
14 | 5c95cb338d3 |
15 | 2e6729c1bcb |
hex | 18db35f9051 |
1708111401041 has 2 divisors, whose sum is σ = 1708111401042. Its totient is φ = 1708111401040.
The previous prime is 1708111400959. The next prime is 1708111401103. The reversal of 1708111401041 is 1401041118071.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1520387641600 + 187723759441 = 1233040^2 + 433271^2 .
It is a cyclic number.
It is not a de Polignac number, because 1708111401041 - 222 = 1708107206737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1708111400995 and 1708111401013.
It is not a weakly prime, because it can be changed into another prime (1708111400041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 854055700520 + 854055700521.
It is an arithmetic number, because the mean of its divisors is an integer number (854055700521).
Almost surely, 21708111401041 is an apocalyptic number.
It is an amenable number.
1708111401041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1708111401041 is an equidigital number, since it uses as much as digits as its factorization.
1708111401041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 29.
The spelling of 1708111401041 in words is "one trillion, seven hundred eight billion, one hundred eleven million, four hundred one thousand, forty-one".
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