17102040121 has 4 divisors (see below), whose sum is σ = 17102682112. Its totient is φ = 17101398132.

The previous prime is 17102040113. The next prime is 17102040139. The reversal of 17102040121 is 12104020171.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 17102040121 - 2³ = 17102040113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17102040821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279225 + ... + 334918.

It is an arithmetic number, because the mean of its divisors is an integer number (4275670528).

Almost surely, 2^17102040121 is an apocalyptic number.

It is an amenable number.

17102040121 is a deficient number, since it is larger than the sum of its proper divisors (641991).

17102040121 is an equidigital number, since it uses as much as digits as its factorization.

17102040121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 641990.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 17102040121 its reverse (12104020171), we get a palindrome (29206060292).

The spelling of 17102040121 in words is "seventeen billion, one hundred two million, forty thousand, one hundred twenty-one".