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17104424153 is a prime number
BaseRepresentation
bin11111110111000000…
…01100110011011001
31122011000222202220212
433323200030303121
5240012213033103
611505131100505
71143602130545
oct177340146331
948130882825
1017104424153
117288002033
1233942a1735
1317c782584b
14b83902a25
156a19527d8
hex3fb80ccd9

17104424153 has 2 divisors, whose sum is σ = 17104424154. Its totient is φ = 17104424152.

The previous prime is 17104424147. The next prime is 17104424167. The reversal of 17104424153 is 35142440171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17101315984 + 3108169 = 130772^2 + 1763^2 .

It is a cyclic number.

It is not a de Polignac number, because 17104424153 - 24 = 17104424137 is a prime.

It is a super-2 number, since 2×171044241532 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (17104424123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8552212076 + 8552212077.

It is an arithmetic number, because the mean of its divisors is an integer number (8552212077).

Almost surely, 217104424153 is an apocalyptic number.

It is an amenable number.

17104424153 is a deficient number, since it is larger than the sum of its proper divisors (1).

17104424153 is an equidigital number, since it uses as much as digits as its factorization.

17104424153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 32.

The spelling of 17104424153 in words is "seventeen billion, one hundred four million, four hundred twenty-four thousand, one hundred fifty-three".