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17114027713 is a prime number
BaseRepresentation
bin11111111000001001…
…10101011011000001
31122011201001200112021
433330010311123001
5240022142341323
611510113001441
71144046556346
oct177404653301
948151050467
1017114027713
117292471362
123397553281
1317c9808b23
14b84cc27cd
156a26ed05d
hex3fc1356c1

17114027713 has 2 divisors, whose sum is σ = 17114027714. Its totient is φ = 17114027712.

The previous prime is 17114027701. The next prime is 17114027717. The reversal of 17114027713 is 31772041171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13643875249 + 3470152464 = 116807^2 + 58908^2 .

It is a cyclic number.

It is not a de Polignac number, because 17114027713 - 213 = 17114019521 is a prime.

It is a super-2 number, since 2×171140277132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (17114027717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8557013856 + 8557013857.

It is an arithmetic number, because the mean of its divisors is an integer number (8557013857).

Almost surely, 217114027713 is an apocalyptic number.

It is an amenable number.

17114027713 is a deficient number, since it is larger than the sum of its proper divisors (1).

17114027713 is an equidigital number, since it uses as much as digits as its factorization.

17114027713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8232, while the sum is 34.

Adding to 17114027713 its reverse (31772041171), we get a palindrome (48886068884).

The spelling of 17114027713 in words is "seventeen billion, one hundred fourteen million, twenty-seven thousand, seven hundred thirteen".