Base | Representation |
---|---|
bin | 11111111000001001… |
… | …11011101101000001 |
3 | 1122011201002222211011 |
4 | 33330010323231001 |
5 | 240022144202231 |
6 | 11510113320521 |
7 | 1144050024352 |
oct | 177404735501 |
9 | 48151088734 |
10 | 17114053441 |
11 | 7292489721 |
12 | 3397566141 |
13 | 17c9817754 |
14 | b84ccbd29 |
15 | 6a27059b1 |
hex | 3fc13bb41 |
17114053441 has 2 divisors, whose sum is σ = 17114053442. Its totient is φ = 17114053440.
The previous prime is 17114053427. The next prime is 17114053469. The reversal of 17114053441 is 14435041171.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12174915600 + 4939137841 = 110340^2 + 70279^2 .
It is a cyclic number.
It is not a de Polignac number, because 17114053441 - 217 = 17113922369 is a prime.
It is not a weakly prime, because it can be changed into another prime (17114053841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8557026720 + 8557026721.
It is an arithmetic number, because the mean of its divisors is an integer number (8557026721).
Almost surely, 217114053441 is an apocalyptic number.
It is an amenable number.
17114053441 is a deficient number, since it is larger than the sum of its proper divisors (1).
17114053441 is an equidigital number, since it uses as much as digits as its factorization.
17114053441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 31.
The spelling of 17114053441 in words is "seventeen billion, one hundred fourteen million, fifty-three thousand, four hundred forty-one".
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