1712731124411 has 4 divisors (see below), whose sum is σ = 1717813412952. Its totient is φ = 1707648835872.

The previous prime is 1712731124341. The next prime is 1712731124413. The reversal of 1712731124411 is 1144211372171.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1712731124411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1712731124413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2541143765 + ... + 2541144438.

It is an arithmetic number, because the mean of its divisors is an integer number (429453353238).

Almost surely, 2^{1712731124411} is an apocalyptic number.

1712731124411 is a deficient number, since it is larger than the sum of its proper divisors (5082288541).

1712731124411 is an equidigital number, since it uses as much as digits as its factorization.

1712731124411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5082288540.

The product of its digits is 9408, while the sum is 35.

Adding to 1712731124411 its reverse (1144211372171), we get a palindrome (2856942496582).

The spelling of 1712731124411 in words is "one trillion, seven hundred twelve billion, seven hundred thirty-one million, one hundred twenty-four thousand, four hundred eleven".