Base | Representation |
---|---|
bin | 11111111011100000… |
… | …00010110110100001 |
3 | 1122020122221112112120 |
4 | 33331300002312201 |
5 | 240101341212004 |
6 | 11512555214453 |
7 | 1144540501413 |
oct | 177560026641 |
9 | 48218845476 |
10 | 17142132129 |
11 | 72a7317651 |
12 | 33a4a47429 |
13 | 1802599065 |
14 | b8891a9b3 |
15 | 6a4e003d9 |
hex | 3fdc02da1 |
17142132129 has 4 divisors (see below), whose sum is σ = 22856176176. Its totient is φ = 11428088084.
The previous prime is 17142132113. The next prime is 17142132197. The reversal of 17142132129 is 92123124171.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 17142132129 - 24 = 17142132113 is a prime.
It is a super-3 number, since 3×171421321293 (a number of 32 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 17142132129.
It is not an unprimeable number, because it can be changed into a prime (17142132229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2857022019 + ... + 2857022024.
It is an arithmetic number, because the mean of its divisors is an integer number (5714044044).
Almost surely, 217142132129 is an apocalyptic number.
It is an amenable number.
17142132129 is a deficient number, since it is larger than the sum of its proper divisors (5714044047).
17142132129 is an equidigital number, since it uses as much as digits as its factorization.
17142132129 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5714044046.
The product of its digits is 6048, while the sum is 33.
The spelling of 17142132129 in words is "seventeen billion, one hundred forty-two million, one hundred thirty-two thousand, one hundred twenty-nine".
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