Base | Representation |
---|---|
bin | 11111111011110110… |
… | …00001100011110001 |
3 | 1122020212100202210211 |
4 | 33331323001203301 |
5 | 240103110313132 |
6 | 11513141024121 |
7 | 1144604120053 |
oct | 177573014361 |
9 | 48225322724 |
10 | 17145010417 |
11 | 72a8a030a7 |
12 | 33a59b5041 |
13 | 18030661a2 |
14 | b890698d3 |
15 | 6a52bd147 |
hex | 3fdec18f1 |
17145010417 has 2 divisors, whose sum is σ = 17145010418. Its totient is φ = 17145010416.
The previous prime is 17145010403. The next prime is 17145010429. The reversal of 17145010417 is 71401054171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17116750561 + 28259856 = 130831^2 + 5316^2 .
It is an emirp because it is prime and its reverse (71401054171) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-17145010417 is a prime.
It is a super-3 number, since 3×171450104173 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (17145010117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8572505208 + 8572505209.
It is an arithmetic number, because the mean of its divisors is an integer number (8572505209).
Almost surely, 217145010417 is an apocalyptic number.
It is an amenable number.
17145010417 is a deficient number, since it is larger than the sum of its proper divisors (1).
17145010417 is an equidigital number, since it uses as much as digits as its factorization.
17145010417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3920, while the sum is 31.
Adding to 17145010417 its reverse (71401054171), we get a palindrome (88546064588).
The spelling of 17145010417 in words is "seventeen billion, one hundred forty-five million, ten thousand, four hundred seventeen".
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