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1720113 = 3573371
BaseRepresentation
bin110100011111100110001
310020101112220
412203330301
5420020423
6100511253
720422623
oct6437461
93211486
101720113
11a7538a
126ab529
13482c25
1432ac13
1523e9e3
hex1a3f31

1720113 has 4 divisors (see below), whose sum is σ = 2293488. Its totient is φ = 1146740.

The previous prime is 1720109. The next prime is 1720123. The reversal of 1720113 is 3110271.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110271 = 31036757.

It is a cyclic number.

It is not a de Polignac number, because 1720113 - 22 = 1720109 is a prime.

It is a D-number.

It is a junction number, because it is equal to n+sod(n) for n = 1720092 and 1720101.

It is not an unprimeable number, because it can be changed into a prime (1720123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286683 + ... + 286688.

It is an arithmetic number, because the mean of its divisors is an integer number (573372).

21720113 is an apocalyptic number.

It is an amenable number.

1720113 is a deficient number, since it is larger than the sum of its proper divisors (573375).

1720113 is an equidigital number, since it uses as much as digits as its factorization.

1720113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 573374.

The product of its (nonzero) digits is 42, while the sum is 15.

The square root of 1720113 is about 1311.5307849990. The cubic root of 1720113 is about 119.8171520857.

Adding to 1720113 its reverse (3110271), we get a palindrome (4830384).

The spelling of 1720113 in words is "one million, seven hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 573371 1720113