Base | Representation |
---|---|
bin | 1010000001100010110… |
… | …0011101011101000001 |
3 | 121110111211010211102022 |
4 | 2200120230131131001 |
5 | 10310143012000001 |
6 | 211040310131225 |
7 | 15304412230130 |
oct | 2403054353501 |
9 | 543454124368 |
10 | 172213000001 |
11 | 67042826899 |
12 | 29461950b15 |
13 | 1331658a943 |
14 | 8499939917 |
15 | 472dc8411b |
hex | 2818b1d741 |
172213000001 has 16 divisors (see below), whose sum is σ = 201029015040. Its totient is φ = 144451356480.
The previous prime is 172212999971. The next prime is 172213000009. The reversal of 172213000001 is 100000312271.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-172213000001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (172213000009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2808611 + ... + 2869271.
It is an arithmetic number, because the mean of its divisors is an integer number (12564313440).
Almost surely, 2172213000001 is an apocalyptic number.
It is an amenable number.
172213000001 is a deficient number, since it is larger than the sum of its proper divisors (28816015039).
172213000001 is an equidigital number, since it uses as much as digits as its factorization.
172213000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69344.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 172213000001 its reverse (100000312271), we get a palindrome (272213312272).
The spelling of 172213000001 in words is "one hundred seventy-two billion, two hundred thirteen million, one", and thus it is an aban number.
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