Search a number
-
+
1723476190441 is a prime number
BaseRepresentation
bin11001000101000111001…
…011111010010011101001
320002202121000111212021211
4121011013023322103221
5211214134401043231
63355430512033121
7235342226622325
oct31050713722351
96082530455254
101723476190441
11604a16418975
1223a0308327a1
13c66a5361615
145d5b9594985
152ec71841eb1
hex191472fa4e9

1723476190441 has 2 divisors, whose sum is σ = 1723476190442. Its totient is φ = 1723476190440.

The previous prime is 1723476190339. The next prime is 1723476190463. The reversal of 1723476190441 is 1440916743271.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1469984080041 + 253492110400 = 1212429^2 + 503480^2 .

It is an emirp because it is prime and its reverse (1440916743271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1723476190441 - 239 = 1173720376553 is a prime.

It is a super-4 number, since 4×17234761904414 (a number of 50 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1723476190481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 861738095220 + 861738095221.

It is an arithmetic number, because the mean of its divisors is an integer number (861738095221).

Almost surely, 21723476190441 is an apocalyptic number.

It is an amenable number.

1723476190441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1723476190441 is an equidigital number, since it uses as much as digits as its factorization.

1723476190441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1016064, while the sum is 49.

The spelling of 1723476190441 in words is "one trillion, seven hundred twenty-three billion, four hundred seventy-six million, one hundred ninety thousand, four hundred forty-one".